Problem: When the atmospheric pressure is 1.00 atm, a water fountain ejects a stream of water that rises to a height of 6.00 m. There is a 2.00-cm-radius pipe that leads from a pressurized tank to the opening that ejects the water. Assume that the atmospheric pressure is that of the eye of a hurricane, 0.877 atm, and the tank’s pressure remains the same. Calculate the new height if the fountain were operating when the eye of a hurricane passes through. 

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When the atmospheric pressure is 1.00 atm, a water fountain ejects a stream of water that rises to a height of 6.00 m. There is a 2.00-cm-radius pipe that leads from a pressurized tank to the opening that ejects the water. Assume that the atmospheric pressure is that of the eye of a hurricane, 0.877 atm, and the tank’s pressure remains the same. Calculate the new height if the fountain were operating when the eye of a hurricane passes through. 

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Based on our data, we think this problem is relevant for Professor Stone's class at UTAH.