How much heat must be added to 0.00200 kg of ice at T = -60.0°C to produce 0.0020 kg of liquid water at 30.0°C? (Note: For ice, c = 2010 J/(kg•K) and for liquid water c = 4190 J/(kg•K). For water, Lf = 3.34 x 105 J/kg and Lv = 2.256 x 106 J/kg.)
(a) 5000 J
(b) 1420 J
(c) 1160 J
(d) 1030 J
(e) 909 J
(f) 493 J
(g) none of the above answers
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