How much heat must be added to 0.00200 kg of ice at T = -60.0°C to produce 0.0020 kg of liquid water at 30.0°C? (Note: For ice, *c* = 2010 J/(kg•K) and for liquid water *c* = 4190 J/(kg•K). For water, *L*_{f }= 3.34 x 10^{5} J/kg and *L*_{v }= 2.256 x 10^{6} J/kg.)

(a) 5000 J

(b) 1420 J

(c) 1160 J

(d) 1030 J

(e) 909 J

(f) 493 J

(g) none of the above answers