Solution: How much heat must be added to 0.00200 kg of ice at T = -60.0°C to produce 0.0020 kg of liquid water at 30.0°C? (Note: For ice, c = 2010 J/(kg•K) and for liquid water c = 4190 J/(kg•K). For water,  Lf = 3.34 x 105 J/kg and Lv = 2.256 x 106 J/kg.) (a) 5000 J (b) 1420 J (c) 1160 J (d) 1030 J (e) 909 J (f) 493 J (g) none of the above answers

Problem

How much heat must be added to 0.00200 kg of ice at T = -60.0°C to produce 0.0020 kg of liquid water at 30.0°C? (Note: For ice, c = 2010 J/(kg•K) and for liquid water c = 4190 J/(kg•K). For water,  L= 3.34 x 105 J/kg and L= 2.256 x 106 J/kg.)

(a) 5000 J

(b) 1420 J

(c) 1160 J

(d) 1030 J

(e) 909 J

(f) 493 J

(g) none of the above answers