Intro to Simple Harmonic Motion (Horizontal Springs) Video Lessons

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Problem: A 0.600 kg block is attached to a spring with spring constant 15 N/m. While the block is sitting at rest, a student hits it with a hammer and almost instantaneously gives it a speed of 44 cm/s.(a) What is the amplitude of the subsequent oscillations? Answer should be in cm.(b) What is the block's speed at the point where x = 1/4 A? Answer should be in cm/s.

FREE Expert Solution

Energy conservation in simple harmonic motion:

E=12kA2=12m(vmax)2 = 12kx2+12m(vx)2

This problem involves the simple harmonic motion of springs. 

We'll apply the conservation of energy to relate the speed and positions.

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Problem Details

A 0.600 kg block is attached to a spring with spring constant 15 N/m. While the block is sitting at rest, a student hits it with a hammer and almost instantaneously gives it a speed of 44 cm/s.
(a) What is the amplitude of the subsequent oscillations? Answer should be in cm.
(b) What is the block's speed at the point where x = 1/4 A? Answer should be in cm/s.

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