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Problem: Two point charges of +2.0 μC and -6.0 μC are located on the x-axis at x = -1.0 cm and x = +2.0 cm respectively. Where should a third charge of +3.0- μC be placed on the +x-axis so that the potential at the origin is equal to zero? A) x = 3.0 cm B) x = 5.0cm C) x = 1.0cm D) x = 2.0 cm  E) x = 4.0cm 

FREE Expert Solution

Potential due to point charge is expressed as:

Vp=kqr

The net potential at the origin is due to three charges:

V0=V1+V2+V3=kq1r1+kq2r2+kq3r3=k(q1r1+q2r2+q3r3)

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Problem Details

Two point charges of +2.0 μC and -6.0 μC are located on the x-axis at x = -1.0 cm and x = +2.0 cm respectively. Where should a third charge of +3.0- μC be placed on the +x-axis so that the potential at the origin is equal to zero? 

A) x = 3.0 cm B) x = 5.0cm C) x = 1.0cm D) x = 2.0 cm  E) x = 4.0cm 

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