From Coulomb's law, the electric force is given by:

$\overline{){\mathbf{F}}{\mathbf{=}}\frac{\mathbf{k}{\mathbf{q}}_{\mathbf{1}}{\mathbf{q}}_{\mathbf{2}}}{{\mathbf{r}}^{\mathbf{2}}}}$, where k is Coulomb's constant and r is the distance between the charges q_{1} and q_{2}.

Let's take,

q_{1} = +3 μC, q_{2} = - 6.0 μC, q_{3} = - 9.0 μC, and q_{4} = - 2.4 μC

**a.**

r_{12} = 15cm = 0.15 m

r_{13} = sqrt(0.15^{2} + 0.15^{2}) = 0.21213 m

r_{14} = 0.15 m

k = 9.0 × 10^{9} Nm^{2}/C^{2}

So,

The electric force on charge +3.0μC along x-axis:

Four charged particles are placed so that each particle is at the corner of a square. The sides of the square are 15 cm. The charge at the Upper left corner is +3.0 μC, the charge to the upper right corner is –6.0 μC, the charge at the lower left corner is –2.4 μC, and the charge at the lower right corner is –9.0 μC.

a. What is the net electric force on the +3.0 μC charge?

b. What is the net electric force on the –6.0 μC charge?

c.. What is the net electric force on the –9.0 μC charge?.

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