The time period of a simple pendulum is expressed as:

$\overline{){\mathbf{T}}{\mathbf{=}}{\mathbf{2}}{\mathbf{\pi}}\sqrt{\frac{\mathbf{l}}{\mathbf{g}}}}$, where l is the length of the pendulum and g is the acceleration due to gravity.

What is the length of a simple pendulum with a period of 2.0 s?

A) 1.6 m

B) 1.2 m

C) 0.87 m

D) 0.99 m

E) 20 m

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