The moment of inertia of a meter stick is expressed as:

$\overline{){\mathbf{I}}{\mathbf{=}}\frac{\mathbf{1}}{\mathbf{12}}{\mathbf{M}}{{\mathbf{L}}}^{{\mathbf{2}}}}$, where M is the mass of the stick and L is the length of the meter stick.

The moment of inertia of the meter stick, is, thus:

The moment of inertia of a meter stick of length L = 100 cm and mass m = 50 g about a perpendicular axis through its center is mL^{2}/12. Two 21 g masses are attached to the stick, at 32 cm to either side of the center. What is the moment of inertia of the system in units of kg cm^{2} about the perpendicular axis through the center of the stick?

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Moment of Inertia & Mass Distribution concept. You can view video lessons to learn Moment of Inertia & Mass Distribution. Or if you need more Moment of Inertia & Mass Distribution practice, you can also practice Moment of Inertia & Mass Distribution practice problems.