# Problem: The moment of inertia of a meter stick of length L = 100 cm and mass m = 50 g about a perpendicular axis through its center is mL2/12. Two 21 g masses are attached to the stick, at 32 cm to either side of the center. What is the moment of inertia of the system in units of kg cm2 about the perpendicular axis through the center of the stick?

###### FREE Expert Solution

The moment of inertia of a meter stick is expressed as:

$\overline{){\mathbf{I}}{\mathbf{=}}\frac{\mathbf{1}}{\mathbf{12}}{\mathbf{M}}{{\mathbf{L}}}^{{\mathbf{2}}}}$, where M is the mass of the stick and L is the length of the meter stick.

The moment of inertia of the meter stick, is, thus:

99% (79 ratings) ###### Problem Details

The moment of inertia of a meter stick of length L = 100 cm and mass m = 50 g about a perpendicular axis through its center is mL2/12. Two 21 g masses are attached to the stick, at 32 cm to either side of the center. What is the moment of inertia of the system in units of kg cm2 about the perpendicular axis through the center of the stick?