The work done in an electric field is expressed as:
, where q is charge and ΔV is the potential difference.
A mass moves from greater potential to lower potential just like a positive test charge q in an electric field.
Therefore, the work done in terms of electric potential difference between two points will be given as:
W = - q(Vf - Vi), where Vf is the final potential while Vi is the initial potential.
How much work does the electric field do in moving a proton from a point with a potential of +125 V to a point where it is -55 V? Express your answer both in joules and electron volts.
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