Simple Harmonic Motion of Pendulums Video Lessons

Concept

# Problem: An object is undergoing simple harmonic motion with period 0.900 s and amplitude 0.320 m. At t = 0 the object is at x = 0.320 m and is instantaneously at rest. Calculate the time it takes the object to go from x = 0.320 m to x = 0.160 m and the time it takes the object to go from x = 0.160 m to x = 0 m.

###### FREE Expert Solution

The displacement x changes with time as:

$\overline{){\mathbf{x}}{\mathbf{=}}{\mathbf{A}}{\mathbf{c}}{\mathbf{o}}{\mathbf{s}}{\mathbf{\omega }}{\mathbf{t}}}$, where A is amplitude, ω is the angular frequency, and t is time.

In our case, we're told that A = 0.320

Therefore, our equation will be:

x = 0.320cosωt

At t = 0. x = 0.320 m

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###### Problem Details
An object is undergoing simple harmonic motion with period 0.900 s and amplitude 0.320 m. At t = 0 the object is at x = 0.320 m and is instantaneously at rest. Calculate the time it takes the object to go from x = 0.320 m to x = 0.160 m and the time it takes the object to go from x = 0.160 m to x = 0 m.