Let's consider the position equation:
We're told that at t = 1 s, v0 = 24 m/s
A body moving in the positive x direction passes the origin at time t=0. Between t=0 and t = 1 second, the body has a constant speed of 24 meters per second. At t = 1 second, the body is given a constant acceleration of 6 meters per second squared in the negative x direction. The position x of the body at t = 11 seconds is
A + 99 m
B + 36 m
C - 36 m
D -99 m
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