Kinematics Equations Video Lessons

Concept

# Problem: A body moving in the positive x direction passes the origin at time t=0. Between t=0 and t = 1 second, the body has a constant speed of 24 meters per second. At t = 1 second, the body is given a constant acceleration of 6 meters per second squared in the negative x direction. The position x of the body at t = 11 seconds is A + 99 m B + 36 m C - 36 m D -99 m

###### FREE Expert Solution

Let's  consider the position equation:

$\overline{){{\mathbf{x}}}_{{\mathbf{f}}}{\mathbf{=}}{{\mathbf{x}}}_{{\mathbf{0}}}{\mathbf{+}}{{\mathbf{v}}}_{{\mathbf{0}}}{\mathbf{t}}{\mathbf{+}}\frac{\mathbf{1}}{\mathbf{2}}{\mathbf{a}}{{\mathbf{t}}}^{{\mathbf{2}}}}$

We're told that at t = 1 s, v0 = 24 m/s

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###### Problem Details

A body moving in the positive x direction passes the origin at time t=0. Between t=0 and t = 1 second, the body has a constant speed of 24 meters per second. At t = 1 second, the body is given a constant acceleration of 6 meters per second squared in the negative x direction. The position x of the body at t = 11 seconds is

A + 99 m

B + 36 m

C - 36 m

D -99 m