Kinematics Equations Video Lessons

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Problem: A body moving in the positive x direction passes the origin at time t=0. Between t=0 and t = 1 second, the body has a constant speed of 24 meters per second. At t = 1 second, the body is given a constant acceleration of 6 meters per second squared in the negative x direction. The position x of the body at t = 11 seconds is A + 99 m B + 36 m C - 36 m D -99 m

FREE Expert Solution

Let's  consider the position equation:

xf=x0+v0t+12at2

We're told that at t = 1 s, v0 = 24 m/s

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Problem Details

A body moving in the positive x direction passes the origin at time t=0. Between t=0 and t = 1 second, the body has a constant speed of 24 meters per second. At t = 1 second, the body is given a constant acceleration of 6 meters per second squared in the negative x direction. The position x of the body at t = 11 seconds is 

A + 99 m 

B + 36 m 

C - 36 m 

D -99 m

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What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Kinematics Equations concept. You can view video lessons to learn Kinematics Equations. Or if you need more Kinematics Equations practice, you can also practice Kinematics Equations practice problems.

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Based on our data, we think this problem is relevant for Professor Chuang's class at CSULB.