Part 1: Torques created by masses A and C
τ = rFsinθ, where θ is the angle between r and F.
We'll take counterclockwise as positive.
τA = rA(mAg)sinθ = (1.0)(60)(9.8)sin60 = 509.2N•m
The torque of mass A about the pivot is 509.2N•m
On a seesaw shown below, mass A is 60 kg, mass B is 30 kg, and mass C is 10 kg. Mass A is 1.0 m from the pivot. Mass C is 3.0 m from the pivot. The seesaw is at an angle of 30° from the horizontal.
Part 1: Calculate the torques of mass A and mass C about the pivot.
Part2: Where should you place mass B in relation to the pivot for the system to be in rotational equilibrium?
Frequently Asked Questions
What scientific concept do you need to know in order to solve this problem?
Our tutors have indicated that to solve this problem you will need to apply the Net Torque & Sign of Torque concept. You can view video lessons to learn Net Torque & Sign of Torque. Or if you need more Net Torque & Sign of Torque practice, you can also practice Net Torque & Sign of Torque practice problems.