Conservation of Energy in Rolling Motion Video Lessons

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Problem: A solid sphere of mass 4.0 kg and radius 0.12 m starts from rest at the top of a ramp inclined 15 degrees, and rolls to the bottom. The upper end of the ramp is 1.2 m higher than the lower end. What is the linear speed of the sphere when it reaches the bottom of the ramp? (Note: I = 0.4 MR2 for a solid sphere and g = 9.8m/s2)a. 4.7m/sb. 4.1 m/sc. 3.4 m/sd. 2.4m/s

FREE Expert Solution

Let's consider the law of conservation of energy.

PE=Ktrans+Krot, where PE is the potential energy, Ktranslational is the translational kinetic energy, and Krot is the rotational kinetic energy.

But, PE = mgh

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Problem Details

A solid sphere of mass 4.0 kg and radius 0.12 m starts from rest at the top of a ramp inclined 15 degrees, and rolls to the bottom. The upper end of the ramp is 1.2 m higher than the lower end. What is the linear speed of the sphere when it reaches the bottom of the ramp? (Note: I = 0.4 MR2 for a solid sphere and g = 9.8m/s2)

a. 4.7m/s

b. 4.1 m/s

c. 3.4 m/s

d. 2.4m/s

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What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Conservation of Energy in Rolling Motion concept. You can view video lessons to learn Conservation of Energy in Rolling Motion. Or if you need more Conservation of Energy in Rolling Motion practice, you can also practice Conservation of Energy in Rolling Motion practice problems.

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