We need to master some concepts before tackling this problem.
One of them is the expression for work, which is:
, where q is charge and ΔV is the potential difference.
The potential difference ΔV for equipotential surfaces is zero.
ΔV = 0.
This means that W = 0.
The electric force is expressed as:
, where E is the electric field.
The electric field and potential are related by:
, where V is the electric potential.
Three points (A, B, and C) are located on equipotential lines as shown.
1. A proton is released from Point A. Indicate the direction of the electric force vector acting on the proton.
The electric force vector at Point A points in which direction?
e) is zero
2. The electric force vector at PointB points in which direction?
e) is zero
3. An electron is released from Point B and a second electron is released from Point C. What can you say about the electric forces experienced by these electrons the instant they are released?
a. The electron released at Point B experiences a greater force.
b. The electron released at Point C experiences a greater force.
c. Electrons released from Points B and C would experience equal forces.
d. Therelationship between the two forces cannot be determined.
Frequently Asked Questions
What scientific concept do you need to know in order to solve this problem?
Our tutors have indicated that to solve this problem you will need to apply the Equipotential Surfaces concept. You can view video lessons to learn Equipotential Surfaces. Or if you need more Equipotential Surfaces practice, you can also practice Equipotential Surfaces practice problems.
What professor is this problem relevant for?
Based on our data, we think this problem is relevant for Professor Perry's class at TEXAS.