The electric force on a charged object is expressed as:
, where q is charge and E is the electric field.
We've been given q = e = 1.60×10-19 C
If the total positive charge is Q= 1.62×10-6 C, and the magnitude of the electric field caused by this charge at point P is 6220 N/C at a distance d= 1.53m from the charge. Now find the magnitude of the force on an electron placed at point P. Recall that the charge on an electron has magnitude e=1.60x10-19 C .
Enter your answer numerically in newtons.
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