Coulomb's Law (Electric Force) Video Lessons

Video Thumbnail

Concept

Problem: If the total positive charge is Q= 1.62×10-6 C, and the magnitude of the electric field caused by this charge at point P is 6220 N/C at a distance d= 1.53m from the charge. Now find the magnitude of the force on an electron placed at point P. Recall that the charge on an electron has magnitude e=1.60x10-19 C .Enter your answer numerically in newtons.

FREE Expert Solution

The electric force on a charged object is expressed as:

F=qE, where q is charge and E is the electric field. 

We've been given q = e = 1.60×10-19 C

97% (391 ratings)
View Complete Written Solution
Problem Details

If the total positive charge is Q= 1.62×10-6 C, and the magnitude of the electric field caused by this charge at point P is 6220 N/C at a distance d= 1.53m from the charge. Now find the magnitude of the force on an electron placed at point P. Recall that the charge on an electron has magnitude e=1.60x10-19 C .
Enter your answer numerically in newtons.

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Coulomb's Law (Electric Force) concept. You can view video lessons to learn Coulomb's Law (Electric Force). Or if you need more Coulomb's Law (Electric Force) practice, you can also practice Coulomb's Law (Electric Force) practice problems.

What professor is this problem relevant for?

Based on our data, we think this problem is relevant for Professor Pandit's class at USF.