In this problem, we're going to use Newton's second law of motion, which states:
, where ΣF is the sum of forces, m is the mass, and a is the acceleration.
We also need to get m in our case.
, where W is weight and g is the acceleration due to gravity.
Taking Newton's equation on block A:
T = 200(1 - aA/g) ........................... (1)
Now, consider block B:
T = 100(1 + aB/g) ................. (2)
Let's equate equations (1) and (2) and remember that |aA| = |aB|.
Each of the systems shown is initially at rest. Neglecting axle friction and the masses of the pulleys, determine for each system:
(a) the acceleration of block A
(b) the velocity of block A after it has moved through 10 ft.
(c) the time required for block A to reach a velocity of 20 ft/s.
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Our tutors have indicated that to solve this problem you will need to apply the Forces in Connected Objects (Systems) concept. You can view video lessons to learn Forces in Connected Objects (Systems). Or if you need more Forces in Connected Objects (Systems) practice, you can also practice Forces in Connected Objects (Systems) practice problems.