Electric Field As Derivative of Potential Video Lessons

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Problem: The electric potential in a region of space is V = (150x2 – 200y2) V, where x and y are in meters. What are the strength and direction of the electric field at (x, y) = (2.0 m,2.0 m)? Give the direction as an angle cw or ccw (specify which) from the positive x-axis.

FREE Expert Solution

We're told that the electric potential in a region of space is:

V=(150x2-200y2)V

We take the components of the electric field in the x and y directions to be Ex and Ey, respectively. 

Therefore, 

Ex=-dVdx

Similarly, 

Ey=-dVdy

The negative sign in these equations is for the potential difference coefficient. 

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The electric potential in a region of space is V = (150x2 – 200y2) V, where x and y are in meters. What are the strength and direction of the electric field at (x, y) = (2.0 m,2.0 m)? Give the direction as an angle cw or ccw (specify which) from the positive x-axis.

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