From Coulomb's law, the electric force is expressed as:

$\overline{){\mathbf{F}}{\mathbf{=}}\frac{\mathbf{k}{\mathbf{q}}_{\mathbf{1}}{\mathbf{q}}_{\mathbf{2}}}{{\mathbf{r}}^{\mathbf{2}}}}$, where **k** is Coulomb's constant and **r** is the distance between the two charges, **q _{1} **and

Two point charges, each with 0.1 C (0.1 Coulombs) of charge, are 0.1 m (0.1 meters) apart. Given that k = 9.0×10^{9} Nm^{2}/C^{2} (the proportionality constant for Coulomb's law), show that the force between the charges is 9.0×10^{9} N.

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