This problem requires us to use the equation for impulse, which is:

$\overline{)\begin{array}{rcl}{\mathbf{I}}& {\mathbf{=}}& \mathbf{F}\mathbf{\u2206}\mathbf{t}\\ & {\mathbf{=}}& \mathbf{m}{\mathbf{v}}_{\mathbf{f}}\mathbf{-}\mathbf{m}{\mathbf{v}}_{\mathbf{i}}\end{array}}$

We will also use the kinematic equation:

$\overline{){{{\mathbf{v}}}_{\mathbf{f}\mathbf{y}}}^{{\mathbf{2}}}{\mathbf{=}}{{{\mathbf{v}}}_{\mathbf{0}\mathbf{y}}}^{{\mathbf{2}}}{\mathbf{+}}{\mathbf{2}}{\mathbf{a}}{\mathbf{y}}}$, where **a** is the acceleration of the ball and **y** is the displacement of the ball.

Just before impact, we can use our kinematic equation to determine the velocity of the ball as:

A ball of mass 0.150 kg is dropped from rest from a height of 1.25 m. It rebounds from the floor to reach a height of 0.960 m. What impulse was given to the ball by the floor?

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Momentum & Impulse in 2D concept. You can view video lessons to learn Momentum & Impulse in 2D. Or if you need more Momentum & Impulse in 2D practice, you can also practice Momentum & Impulse in 2D practice problems.