Momentum & Impulse in 2D Video Lessons

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# Problem: A ball of mass 0.150 kg is dropped from rest from a height of 1.25 m. It rebounds from the floor to reach a height of 0.960 m. What impulse was given to the ball by the floor?

###### FREE Expert Solution

This problem requires us to use the equation for impulse, which is:

$\overline{)\begin{array}{rcl}{\mathbf{I}}& {\mathbf{=}}& \mathbf{F}\mathbf{∆}\mathbf{t}\\ & {\mathbf{=}}& \mathbf{m}{\mathbf{v}}_{\mathbf{f}}\mathbf{-}\mathbf{m}{\mathbf{v}}_{\mathbf{i}}\end{array}}$

We will also use the kinematic equation:

$\overline{){{{\mathbf{v}}}_{\mathbf{f}\mathbf{y}}}^{{\mathbf{2}}}{\mathbf{=}}{{{\mathbf{v}}}_{\mathbf{0}\mathbf{y}}}^{{\mathbf{2}}}{\mathbf{+}}{\mathbf{2}}{\mathbf{a}}{\mathbf{y}}}$, where a is the acceleration of the ball and y is the displacement of the ball.

Just before impact, we can use our kinematic equation to determine the velocity of the ball as:

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###### Problem Details

A ball of mass 0.150 kg is dropped from rest from a height of 1.25 m. It rebounds from the floor to reach a height of 0.960 m. What impulse was given to the ball by the floor?