Electric potential difference is expressed as:

$\overline{){\mathbf{\u2206}}{\mathbf{V}}{\mathbf{=}}\frac{\mathbf{\lambda}}{\mathbf{2}\mathbf{\pi}{\mathbf{\epsilon}}_{\mathbf{0}}}{\mathbf{l}}{\mathbf{n}}{\mathbf{\left(}}\frac{\mathbf{d}}{\mathbf{r}}{\mathbf{\right)}}}$

Solving for the line charge density, λ:

The potential difference between the surface of a 2.2 cm – diameter power line and a point 1.9 m distant is 3.8 kV.

Part A. What is the magnitude of the line charge density on the power line?

Express your answer using two significant figures.

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