Electric Field Video Lessons

Concept

# Problem: (a) If the total positive charge is Q = .62x10-6 C, what is the magnitude of the electric field caused by this charge at point P, a distance d=1.53 m from the charge?Enter your answer numerically in newtons per coulomb.(b) What is the direction of the electric field at point P?Enter the letter of the vector that represents the direction of Ep.

###### FREE Expert Solution

(a)

In this problem, we are talking about an electric field and a charge. Thus, the expression to be used is:

Electric field:

$\overline{){\mathbf{E}}{\mathbf{=}}\frac{\mathbf{k}\mathbf{q}}{{\mathbf{r}}^{\mathbf{2}}}}$

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###### Problem Details

(a) If the total positive charge is Q = .62x10-6 C, what is the magnitude of the electric field caused by this charge at point P, a distance d=1.53 m from the charge?