Kirchhoff's Loop Rule Video Lessons

Concept

# Problem: Calculate the three currents I1,I2, and I3 indicated in the circuit diagram shown in the figure (Figure 1) .

###### FREE Expert Solution

We need Kirchhoff's junction rule to solve this problem.

Kirchhoff's junction rule states that current INTO a junction is always EQUAL to current OUT of the junction.

That is,

$\overline{){\mathbf{\sum }}{{\mathbf{I}}}_{\mathbf{i}\mathbf{n}}{\mathbf{=}}{\mathbf{\sum }}{{\mathbf{I}}}_{\mathbf{o}\mathbf{u}\mathbf{t}}}$

We'll also use Kirchoff's loop rule, which is written as:

$\overline{){\mathbf{\Sigma }}{\mathbf{V}}{\mathbf{=}}{\mathbf{0}}}$

We also need to know, from Ohm's law, that:

$\overline{){\mathbf{V}}{\mathbf{=}}{\mathbf{I}}{\mathbf{R}}}$

We can get the current through the 5.00-Ω and 8.00-Ω resistors in terms of I1, I2, and I3 using the junction rule.

We then apply Kirchhoff's loop rule to the three loops visible in the circuit.

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###### Problem Details

Calculate the three currents I1,I2, and I3 indicated in the circuit diagram shown in the figure (Figure 1) .