The work done to decrease the volume from V_{1} to V_{2} is given as:

$\overline{){\mathbf{W}}{\mathbf{=}}{\mathbf{-}}{\mathbf{P}}{\mathbf{(}}{{\mathbf{V}}}_{{\mathbf{2}}}{\mathbf{-}}{{\mathbf{V}}}_{{\mathbf{1}}}{\mathbf{)}}}$, where P is pressure, V_{1} is initial volume, and V_{2} is the final volume.

We also need to note that:

$\overline{){\mathbf{1}}{\mathbf{a}}{\mathbf{t}}{\mathbf{m}}{\mathbf{L}}{\mathbf{=}}{\mathbf{101}}{\mathbf{.}}{\mathbf{325}}{\mathbf{J}}}$

How much work must be done on a system to decrease its volume from 15.0 L to 6.0 L by exerting a constant pressure of 3.0 atm?

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