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Problem: How much work must be done on a system to decrease its volume from 15.0 L to 6.0 L by exerting a constant pressure of 3.0 atm?

FREE Expert Solution

The work done to decrease the volume from V1 to V2 is given as:

W=-P(V2-V1), where P is pressure, V1 is initial volume, and V2 is the final volume.

We also need to note that:

1atmL=101.325J

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Problem Details

How much work must be done on a system to decrease its volume from 15.0 L to 6.0 L by exerting a constant pressure of 3.0 atm?

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