Electric Field As Derivative of Potential Video Lessons

Concept

Problem: The electric field in a certain region is given by the equation E = (axn − b)i, where a = 11 N/(C⋅mn), b = 9 N/C and n = 3.Calculate the electric potential difference (ΔV = V2 − V1), in volts, between the points x2 = 1.5 m and x1 = 0.65 m, i.e., ΔV = V(x2) − V(x1).

FREE Expert Solution

In this problem, we are dealing with an electric field and electric potential. Thus, it is necessary to recall the relationship between the two.

Electric field:

$\overline{){\mathbf{E}}{\mathbf{=}}{\mathbf{-}}\frac{\mathbf{∆}\mathbf{V}}{\mathbf{∆}\mathbf{x}}}$

Power rule of derivation:

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Problem Details

The electric field in a certain region is given by the equation E = (axn − b)i, where a = 11 N/(C⋅mn), b = 9 N/C and n = 3.

Calculate the electric potential difference (ΔV = V2 − V1), in volts, between the points x2 = 1.5 m and x1 = 0.65 m, i.e., ΔV = V(x2) − V(x1).