As the question states, we use Coulomb's law to get the electric force as:

$\overline{){\mathbf{F}}{\mathbf{=}}\frac{\mathbf{k}{\mathbf{q}}_{\mathbf{1}}{\mathbf{q}}_{\mathbf{2}}}{{\mathbf{r}}^{\mathbf{2}}}}$, where F is the electric force, k is Coulomb constant, and q_{1} and q_{2} are charges separated by distance r.

The distance of separation from charge 1 to charge 3 is:

r_{13} = - 1.650 - (-1.210) = - 0.440 m

The electric force that q_{1} exerts on q_{3} is:

What is the net force exerted by these two charges on a third charge q_{3}= 45.0nC placed between q_{1} and q_{2} and at x_{3}=-1.210m?

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