# Problem: A 9.0 V battery supplies a 2.5 mA current to a circuit for 5.0 h. a. How much charge has been transferred from the negative to the positive terminal? b. How much electric potential energy has been gained by the charges that passed through the battery?

###### FREE Expert Solution

Current is expressed as:

$\overline{){\mathbf{i}}{\mathbf{=}}\frac{\mathbf{∆}\mathbf{q}}{\mathbf{∆}\mathbf{t}}}$

This is because the current is defined as the flow of charge carriers per second.

The charge is transferred from the negative terminal to the positive terminal of the battery and is given by:

$\overline{){\mathbf{∆}}{\mathbf{q}}{\mathbf{=}}{\mathbf{i}}{\mathbf{∆}}{\mathbf{t}}}$

The work done in moving the charge through the battery with a potential difference ΔV is:

$\overline{){\mathbf{W}}{\mathbf{=}}{\mathbf{q}}{\mathbf{∆}}{\mathbf{V}}}$

87% (146 ratings) ###### Problem Details

A 9.0 V battery supplies a 2.5 mA current to a circuit for 5.0 h.

a. How much charge has been transferred from the negative to the positive terminal?

b. How much electric potential energy has been gained by the charges that passed through the battery?

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