The electric field is expressed as:

$\overline{){\mathbf{E}}{\mathbf{=}}\frac{\mathbf{k}\mathbf{q}}{{\mathbf{r}}^{\mathbf{2}}}}$

Here, k is Coulomb's constant, q is the charge, and r is the distance between the charge and the point where the electric field is felt.

In this problem, r = d.

Electric potential:

$\overline{){\mathbf{P}}{\mathbf{=}}\frac{\mathbf{k}\mathbf{Q}}{\mathbf{d}}}$

**1.**

The electric field at point P is due to charge 2Q directed towards Q.

It is also due to charge Q directed towards +2Q.

And due to charge, -Q towards charge -Q

1. What is the magnitude of the electric field at point P?

2. What is the voltage at point P? (As always when dealing with point charges, we assume that the zero of voltage is at r = ∞.)

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