The potential difference between points A and B can be expressed as:

$\overline{){{\mathbf{V}}}_{\mathbf{A}\mathbf{B}}{\mathbf{=}}{\mathbf{-}}{{\mathbf{\int}}}_{{\mathbf{B}}}^{{\mathbf{A}}}{\mathbf{E}}{\mathbf{\xb7}}{\mathbf{d}}{\mathbf{l}}}$

Let A = (x_{1}, y_{1}) and B = (x_{2}, y_{2}) be two points near and on the same side of a charged sheet with surface charge density

+σ. The electric field E due to such a charges sheet has magnitude E = σ/2e_{0} everywhere, and the field points away from the sheet, as shown in the diagram.

Part A. What is the potential difference V_{AB} = V_{A} – V_{B} between points A and B?

Part B. If the potential at y = ±∞ is taken to be zero, what is the value of the potential at a point VA at some positive distance y1 from the surface of the sheet?

Choices are

a. ∞

b. -∞

c. 0

d. -E•y_{1}

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