Both the springs will experience a force, F.
For spring 1, we'll have:
The period of an object oscillating on the end of a spring is given by the formula:
Here, the spring constant k comes from the usual definition by Hooke’s law, in terms of the force of the spring at some displacement from the equilibrium position x1:
F = -k (x-x0)
If we let M denote the mass of the object oscillating, this accurately describes an ideal situation in which springs are massless. There is actually a correction when we consider the case of springs whose mass of the springs, then the effective mass M (which we plug into the above formula) is defined by:
M = MG + Ms/3
We will also make use of the potential energy stored in a spring:
U = ½ k (x-x0)2
Note that the kinetic energy also uses the same effective mass M in place of the mass of the glider.
Effective Spring Constant: In Part 1, you measured the keffective fo the two springs acting together. If the two springs k1 and k2 individually, how would they combine to get keff?
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