Solving Capacitor Circuits Video Lessons

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Problem: A 0.50-μF and 1.4-μF capacitor (C1 and C2, respectively) are connected in series to a 9.0-V battery. Part A. Calculate the potential difference across each capacitor. Express your answers using two significant figures separated by a comma.Part B. Calculate the charge on each capacitor assuming the two capacitors are in parallel.

FREE Expert Solution

For two capacitors in series, the equivalent capacitance is given by:

Ceq=C1C2C1+C2

Potential difference:

V=QC, where Q is charge and C is capacitance. 

Charge, Q:

Q=CV

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Problem Details

A 0.50-μF and 1.4-μF capacitor (C1 and C2, respectively) are connected in series to a 9.0-V battery. 

Part A. Calculate the potential difference across each capacitor. Express your answers using two significant figures separated by a comma.

Part B. Calculate the charge on each capacitor assuming the two capacitors are in parallel.

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