# Problem: A small block is attached to an ideal spring and is moving in SHM on a horizontal, frictionless surface. The amplitude of the motion is 0.300m and the period is 3.39 s.Part A. What is the acceleration of the block when x = 0.160 m? Express your answer with the appropriate units.Part B. What is the speed of the block when x = 0.160 m? Express your answer with the appropriate units

###### FREE Expert Solution

Angular frequency:

$\overline{){\mathbf{\omega }}{\mathbf{=}}\frac{\mathbf{2}\mathbf{\pi }}{\mathbf{T}}}$, where T is period.

Acceleration:

$\overline{){\mathbf{a}}{\mathbf{=}}{\mathbf{-}}{{\mathbf{\omega }}}^{{\mathbf{2}}}{\mathbf{x}}}$

Speed:

$\overline{){\mathbf{v}}{\mathbf{=}}{\mathbf{\omega }}\sqrt{{\mathbf{A}}^{\mathbf{2}}\mathbf{-}{\mathbf{x}}^{\mathbf{2}}}}$

95% (311 ratings) ###### Problem Details

A small block is attached to an ideal spring and is moving in SHM on a horizontal, frictionless surface. The amplitude of the motion is 0.300m and the period is 3.39 s.

Part A. What is the acceleration of the block when x = 0.160 m? Express your answer with the appropriate units.

Part B. What is the speed of the block when x = 0.160 m? Express your answer with the appropriate units

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Our tutors have indicated that to solve this problem you will need to apply the Intro to Simple Harmonic Motion (Horizontal Springs) concept. You can view video lessons to learn Intro to Simple Harmonic Motion (Horizontal Springs). Or if you need more Intro to Simple Harmonic Motion (Horizontal Springs) practice, you can also practice Intro to Simple Harmonic Motion (Horizontal Springs) practice problems.