The person's far point can be calculated from the relation:

$\overline{){\mathbf{P}}{\mathbf{=}}\frac{\mathbf{1}}{{\mathbf{s}}_{\mathbf{o}}}{\mathbf{+}}\frac{\mathbf{1}}{{\mathbf{s}}_{\mathbf{i}}}}$, where P is the power of the lens of the eye, s_{o} is the object distance and s_{i} is the image distance.

Let's take the far point to be x and the distance at which the person is wearing glasses to be y.

We're told that the myopic person is wearing the glasses at 1.75 cm.

Therefore, y = 1.75 cm = 1.75 × 10^{-2} m

Repeat the previous problem for glasses that are 1.75 cm from the eyes.

Reference previous problem:

A myopic person sees that her contact lens prescription is -4.00 D. What is her far point?

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