Problem: Repeat the previous problem for glasses that are 1.75 cm from the eyes.Reference previous problem:A myopic person sees that her contact lens prescription is -4.00 D. What is her far point?

The person's far point can be calculated from the relation:

$\boxed{\mathbf{P}\mathbf{=}\frac{\mathbf{1}}{{\mathbf{s}}_{\mathbf{o}}}\mathbf{+}\frac{\mathbf{1}}{{\mathbf{s}}_{\mathbf{i}}}}$, where P is the power of the lens of the eye, s_o is the object distance and s_i is the image distance. 

Let's take the far point to be x and the distance at which the person is wearing glasses to be y.

We're told that the myopic person is wearing the glasses at 1.75 cm.

Therefore, y = 1.75 cm = 1.75 × 10^-2 m