Young's Double Slit Experiment Video Lessons

Concept

# Problem: Two slits spaced 0.260 mm apart are placed 0.800 m from a screen and illuminated by coherent light with a wavelength of 610 nm. The intensity at the center of the central maximum ( θ =0o) is I0.A. What is the distance on the screen from the center of the central maximum to the first minimum?B. What is the distance on the screen from the center of the central maximum to the point where the intensity has fallen to I0/2 ?

###### FREE Expert Solution

The distance of an nth dark fringe from the central fringe is given by:

$\overline{){{\mathbf{y}}}_{{\mathbf{n}}}{\mathbf{=}}\frac{\mathbf{\left(}\mathbf{2}\mathbf{n}\mathbf{-}\mathbf{1}\mathbf{\right)}\mathbf{D}\mathbf{\lambda }}{\mathbf{2}\mathbf{d}}}$, where D is the distance between the slit and the screen, d is the space between two slits, and λ is the wavelength of the light.

A.

For the first minimum, n = 1.

We're given:

d = 0.260 mm = 0.260 × 10-3 m

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###### Problem Details

Two slits spaced 0.260 mm apart are placed 0.800 m from a screen and illuminated by coherent light with a wavelength of 610 nm. The intensity at the center of the central maximum ( θ =0o) is I0.

A. What is the distance on the screen from the center of the central maximum to the first minimum?

B. What is the distance on the screen from the center of the central maximum to the point where the intensity has fallen to I0/2 ?