Kinetic energy:

$\overline{){\mathbf{K}}{\mathbf{=}}\frac{\mathbf{1}}{\mathbf{2}}{{\mathbf{mv}}}^{{\mathbf{2}}}}$, where m is mass and v is velocity.

Kinetic energy can also be expressed as:

$\overline{){\mathbf{K}}{\mathbf{=}}{\mathbf{q}}{\mathbf{V}}}$, where q is charge and V is the energy in electron volt.

A bare helium nucleus has two positive charges and a mass of 6.64x10^{-27} kg.

(a) Calculate its kinetic energy in joules at 2.00% of the speed of light

(b) What is this in electron volts?

(c) What voltage would be needed to obtain this energy?

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