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Problem: Charges -q and +2q in the figure are located at x=+-a.  Determine the electric field at points 1 to 4. Write each field in component form.

FREE Expert Solution

The electric field due to point charge at distance r:

E=kqr2, where q is the charge, r is the distance from the point to the charge, and k is the electrostatic constant.

k is also expressed as:

k=14πε0

Therefore, we have the electric field written as:

E=14πε0qr

We'll consider the following figure.

At point 1

The distance between charge 2q and point 1 is:

r12=(-a)2+(2a)2=a2+4a2

r12 = 5a2

 The distance between charge, -q and point 1 is:

r22=a2+(2a)2=a2+4a2

r22 = 5a2

From our figure:

sinθ=ar2=a5a2=aa5

sinθ = 1/sqrt(5)

Also,

cosθ=2ar2=2a5a2=2aa5

cosθ = 2/sqrt(5)

The electric field at point 1 due to charge, +2q is:

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Problem Details

Charges -q and +2q in the figure are located at x=

Charges -q and +2q in the figure are located at x=+-a.  Determine the electric field at points 1 to 4. Write each field in component form.

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