From Ohm's law:

$\overline{){\mathbf{R}}{\mathbf{=}}\frac{\mathbf{V}}{\mathbf{i}}}$, where R is resistance, V is voltage, and i is current.

Resistance:

$\overline{){\mathbf{R}}{\mathbf{=}}{\mathbf{\rho}}\frac{\mathbf{l}}{\mathbf{A}}}$ where ρ is the resistivity, l is the length, and A is the cross-sectional area.

Consider two wires of the same diameter, one is aluminum with a resistivity of 2.65x10^{-8} Ωm and another is copper with resistivity of 1.72x10^{-8} Ωm. When they are connected to a 1.5-volt battery separately there is a current of 0.010 an in each

a. Calculate the resistance in each wire

b. Calculate the ratio of the length of the wires

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