Resistors and Ohm's Law Video Lessons

Concept

# Problem: Consider two wires of the same diameter, one is aluminum with a resistivity of 2.65x10-8 Ωm and another is copper with resistivity of 1.72x10-8 Ωm. When they are connected to a 1.5-volt battery separately there is a current of 0.010 an in eacha. Calculate the resistance in each wireb. Calculate the ratio of the length of the wires

###### FREE Expert Solution

From Ohm's law:

$\overline{){\mathbf{R}}{\mathbf{=}}\frac{\mathbf{V}}{\mathbf{i}}}$, where R is resistance, V is voltage, and i is current.

Resistance:

$\overline{){\mathbf{R}}{\mathbf{=}}{\mathbf{\rho }}\frac{\mathbf{l}}{\mathbf{A}}}$ where ρ is the resistivity, l is the length, and A is the cross-sectional area.

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###### Problem Details

Consider two wires of the same diameter, one is aluminum with a resistivity of 2.65x10-8 Ωm and another is copper with resistivity of 1.72x10-8 Ωm. When they are connected to a 1.5-volt battery separately there is a current of 0.010 an in each
a. Calculate the resistance in each wire
b. Calculate the ratio of the length of the wires

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