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Problem: A racing car undergoing constant acceleration covers 140 m in 3.6 s. (a) If it’s moving at 53 m/s at the end of this interval, what was its speed at the beginning of the interval?(b) How far did it travel from rest to the end of the 140-m distance?

FREE Expert Solution

Uniform accelerated motion (UAM) equations, a.k.a. "kinematics equations":

 vf = v0 +atx= (vf+v02)tx= v0t+12at2 vf2= v02 +2ax

(a)

Using the second kinematic equation, we can solve and determine v0 as:

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Problem Details

A racing car undergoing constant acceleration covers 140 m in 3.6 s. 

(a) If it’s moving at 53 m/s at the end of this interval, what was its speed at the beginning of the interval?

(b) How far did it travel from rest to the end of the 140-m distance?

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