# Problem: The 7 Li nucleus has an excited state 0.48 MeV above the ground state. What wavelength gamma photon is emitted when the nucleus decays from the excited state to the ground state?

###### FREE Expert Solution

Energy is expressed as:

$\overline{){\mathbf{E}}{\mathbf{=}}\frac{\mathbf{hc}}{\mathbf{\lambda }}}$, where h is Plank's constant and c is the velocity of light in a vacuum.

The energy of the nucleus is initially, E = 0.48 MeV = 0.48 × 106 eV

91% (300 ratings) ###### Problem Details
The 7 Li nucleus has an excited state 0.48 MeV above the ground state. What wavelength gamma photon is emitted when the nucleus decays from the excited state to the ground state?

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