We're going to use Kirchhoff's loop rule, which is:

$\overline{){\mathbf{\Sigma}}{\mathbf{V}}{\mathbf{=}}{\mathbf{0}}}$

We'll also use Ohm's law to help get the voltages.

From Ohm's law:

$\overline{){\mathbf{V}}{\mathbf{=}}{\mathbf{i}}{\mathbf{R}}}$, where i is the current and R resistance.

For the circuit shown in Fig. let R_{1} = 5 Ω, R_{2} = 15 Ω, R_{3} = 10 Ω, ε_{1} = 60 V, ε_{2} = 80 V, ε_{3} = 10 V and I_{1} = 2A. Find the value of the current I_{2} in the circuit

a. 4 A

b. 2 A

c. - 2 A

d. - 1 A

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