The angular momentum is:

$\overline{)\begin{array}{rcl}{\mathbf{L}}& {\mathbf{=}}& \mathbf{r}\mathbf{\times}\mathbf{m}\mathbf{v}\end{array}}$

r = [(2)cos(30°)i + (2)sin(30°)j]km

r = (1.73205i + j)km = (1732.05i + 1000j) m

You are standing in a field and see a 4000 kg airplane flying at horizontally at 250 m/s. The distance from you to the airplane is 2km, along a line 30° from the horizontal. The figure shows the airplane, flying from right to left of the page.

What is the magnitude and direction of the angular momentum of the airplane with respect to you, the observer?

a) 10^{6} kg m/s

b) 10^{7} kg m/s

c) 10^{9} kg m/s

d) 10^{8} kg m/s

e) 2 x 10^{6} kg m/s

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