# Problem: Consider a generator that rotates its 200 turn, 0.11 m diameter coil at 3250 rpm in a 0.75 T fieldCalculate the peak voltage of the generator

###### FREE Expert Solution

Peak voltage:

$\overline{){{\mathbf{\epsilon }}}_{{\mathbf{0}}}{\mathbf{=}}{\mathbf{N}}{\mathbf{B}}{\mathbf{A}}{\mathbf{\omega }}}$, where N is the number of turns, B is the magnetic field, A is the area, and ω is the angular velocity.

Area:

$\overline{){\mathbf{A}}{\mathbf{=}}{\mathbf{\pi }}{{\mathbf{r}}}^{{\mathbf{2}}}}$

Angular velocity:

$\overline{){\mathbf{\omega }}{\mathbf{=}}{\mathbf{2}}{\mathbf{\pi }}{\mathbf{f}}}$

The number of turns, N = 200

The magnetic field B = 0.75 T

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###### Problem Details

Consider a generator that rotates its 200 turn, 0.11 m diameter coil at 3250 rpm in a 0.75 T field

Calculate the peak voltage of the generator