Magnetic Force on Current-Carrying Wire Video Lessons

Concept

# Problem: A particle with a charge of q = -5.00 nC is moving in a uniform magnetic field of B = (-1.30 T) k. The magnetic force on the particle is measured to be F = (-7.60x10-7 N) JA) Can vy, the y component of velocity be determined?B) Calculate vx, the x component of the velocity of the particle.C) Can vz, the z component of velocity be determined?

###### FREE Expert Solution

The magnetic force:

$\overline{){\mathbf{F}}{\mathbf{=}}{\mathbf{q}}{\mathbf{\left(}}{\mathbf{v}}{\mathbf{×}}{\mathbf{B}}{\mathbf{\right)}}}$

We have the velocity, v as:

$\overline{){\mathbf{v}}{\mathbf{=}}{{\mathbf{v}}}_{{\mathbf{x}}}{\mathbf{i}}{\mathbf{+}}{{\mathbf{v}}}_{{\mathbf{y}}}{\mathbf{j}}{\mathbf{+}}{{\mathbf{v}}}_{{\mathbf{z}}}{\mathbf{k}}}$

Now, we have force as:

$\mathbit{F}\mathbf{=}\mathbit{q}\mathbf{|}\begin{array}{ccc}\mathbf{i}& \mathbf{j}& \mathbf{k}\\ {\mathbf{v}}_{\mathbf{x}}& {\mathbf{v}}_{\mathbf{y}}& {\mathbf{v}}_{\mathbf{z}}\\ {\mathbf{B}}_{\mathbf{x}}& {\mathbf{B}}_{\mathbf{y}}& {\mathbf{B}}_{\mathbf{z}}\end{array}\mathbf{|}$

85% (490 ratings)
###### Problem Details

A particle with a charge of q = -5.00 nC is moving in a uniform magnetic field of B = (-1.30 T) k. The magnetic force on the particle is measured to be F = (-7.60x10-7 N) J

A) Can vy, the y component of velocity be determined?

B) Calculate vx, the x component of the velocity of the particle.

C) Can vz, the z component of velocity be determined?