The energy released in the decay:
, where m is the mass and c is the speed of light in a vacuum.
The reaction for α-decay can be expressed as:
The isotope 21884Po can decay by either α or β−emission.
What is the energy release in each case? The mass of 21884Po, 21482Pb, 42He and 21885At is 218.008973 u, 213.999798 u, 4.002603 u and 218.008681 u, respectively.
Express your answers using three significant figures separated by a comma.
MeV for units
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