where ρ is the resistivity, l is the length, and A is the cross-sectional area.
When the wire is stretched to double its length, the cross-sectional area will be reduced by half.
Since the density remains constant, the volume will be constant after the wire is stretched.
This means that,
Vi = Vf
A uniform wire of resistance R is stretched unit its length doubles. Assuming its density and resistivity remain constant, what's its new resistance?
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