We get the repulsive force from Coulomb's law:

$\overline{){\mathbf{F}}{\mathbf{=}}\frac{\mathbf{k}{\mathbf{q}}_{\mathbf{1}}{\mathbf{q}}_{\mathbf{2}}}{{\mathbf{r}}^{\mathbf{2}}}}$

Suppose you have two small pith balls that are 7.5 cm apart and have equal charges of -25 nC? What is the magnitude of the repulsive force, in newtons, between the two pith balls?

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