In this problem, we'll use the kinematic equations:

$\overline{)\mathbf{}{\mathbf{\u2206}}{\mathbf{y}}{\mathbf{=}}{\mathbf{}}{{\mathbf{v}}}_{{\mathbf{0}}}{\mathbf{t}}{\mathbf{-}}\frac{\mathbf{1}}{\mathbf{2}}{\mathbf{g}}{{\mathbf{t}}}^{{\mathbf{2}}}\phantom{\rule{0ex}{0ex}}{\mathbf{}}{{{\mathbf{v}}}_{{\mathbf{f}}}}^{{\mathbf{2}}}{\mathbf{=}}{\mathbf{}}{{{\mathbf{v}}}_{{\mathbf{0}}}}^{{\mathbf{2}}}{\mathbf{}}{\mathbf{-}}{\mathbf{2}}{\mathbf{g}}{\mathbf{\u2206}}{\mathbf{y}}}$

A man stands on the roof of a 18.0-m-tall building and throws a rock with a velocity of magnitude 30.0 m/s at an angle of 41.0° above the horizontal. You can ignore air resistance. Assume that the rock is thrown from the level of the roof.

1.) Calculate the magnitude of the velocity of the rock just before it strikes the ground? Express with appropriate units

2.) Calculate the horizontal distance from the base of the building to the point where the rock strikes the ground? Express with appropriate units.

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Projectile Motion: Positive Launch concept. If you need more Projectile Motion: Positive Launch practice, you can also practice Projectile Motion: Positive Launch practice problems.