To get the components, we'll use the equation:

$\overline{)\begin{array}{rcl}{\mathit{A}}_{\mathit{x}}& {\mathbf{=}}& \mathbf{\left|}\stackrel{\mathbf{\rightharpoonup}}{\mathit{A}}\mathbf{\right|}\mathbf{}\mathbf{cos}\mathbf{}\mathit{\theta}\\ {\mathit{A}}_{\mathit{y}}& {\mathbf{=}}& \mathbf{\left|}\stackrel{\mathbf{\rightharpoonup}}{\mathit{A}}\mathbf{\right|}\mathbf{}\mathbf{sin}\mathbf{}\mathit{\theta}\end{array}}$

Two forces, F_{1} and F_{2}, act at a point. F_{1} has a point magnitude of 9.00 N and is directed at an angle of 55.0° above the negative x axis in the second quadrant. F_{2} has a magnitude of 5.20 N and is directed at an angle of 53.0° below the negative x axis in the third quadrant.

Part A. What is the x component of the resultant force. Express your answer in newtons.

Part B. What is the y component of the resultant force? Express your answer in newtons.

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