Position Functions and Instantaneous Velocity Video Lessons

Concept

# Problem: A small object moves along the x-axis with acceleration ax(t) =-(0.0320m/s3)(15.0s-t). at t=0 the object is at x=-14.0m and has velocity v0x =4.50 m/s. What is the x-coordinate of the object when t=10.0s?

###### FREE Expert Solution

In this problem, we are given an acceleration function. We need to determine the position function with the aid of the diagram below:

2D&3D Motion with Calculus

$\mathbit{P}\begin{array}{c}{\mathbf{←}}\\ {\mathbf{\to }}\end{array}\underset{\frac{\mathbit{d}}{\mathbit{d}\mathbit{t}}}{\overset{{\mathbf{\int }}{\mathbit{d}}{\mathbit{t}}}{\mathbit{V}}}\begin{array}{c}{\mathbf{←}}\\ {\mathbf{\to }}\end{array}\mathbit{A}$

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###### Problem Details

A small object moves along the x-axis with acceleration ax(t) =-(0.0320m/s3)(15.0s-t). at t=0 the object is at x=-14.0m and has velocity v0x =4.50 m/s.

What is the x-coordinate of the object when t=10.0s?