Electric Field Video Lessons

Video Thumbnail

Concept

Problem: A point charge q1 = -4.00 nC is at the point x = 0.600 meters, y = 0.800 meters, and a second point charge q2 = +6.00 nC is at the point x = 0.600 meters, y = 0.A) Calculate the magnitude E of the net electric field at the origin due to these two point charges.B) What is the direction, relative to the negative x-axis, of the net electric field at the origin due to these two point charges.

FREE Expert Solution

The electric field is expressed as:

E=kqr2, where k is the Coulomb constant, r is the distance of the charge, and E is the electric field.

A)

From the given information, the distance of charge q1 from the origin is given by:

r1 = sqrt(0.6002 + 0.8002) = 1.0 m

The distance of q2 from the origin:

r2 = sqrt(0.6002 + 02) = 0.600 m

E1 = kq/r12 = (9.0 × 109)(4.00 × 10-9)/1.0= 36.0 N/C

E2 = (9.0 × 109)(6.00 × 10-9)/0.600= 150 N/C

Calculate the x and y components of the electric field at the origin due to the two charges.

85% (324 ratings)
View Complete Written Solution
Problem Details

A point charge q1 = -4.00 nC is at the point x = 0.600 meters, y = 0.800 meters, and a second point charge q2 = +6.00 nC is at the point x = 0.600 meters, y = 0.

A) Calculate the magnitude E of the net electric field at the origin due to these two point charges.

B) What is the direction, relative to the negative x-axis, of the net electric field at the origin due to these two point charges.

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Electric Field concept. You can view video lessons to learn Electric Field. Or if you need more Electric Field practice, you can also practice Electric Field practice problems.