The electric field is expressed as:

$\overline{){\mathbf{E}}{\mathbf{=}}{\mathbf{k}}\frac{\mathbf{q}}{{\mathbf{r}}^{\mathbf{2}}}}$, where k is the Coulomb constant, r is the distance of the charge, and E is the electric field.

**A)**

From the given information, the distance of charge q_{1} from the origin is given by:

r_{1} = sqrt(0.600^{2} + 0.800^{2}) = 1.0 m

The distance of q_{2} from the origin:

r_{2} = sqrt(0.600^{2} + 0^{2}) = 0.600 m

E_{1} = kq/r_{1}^{2} = (9.0 × 10^{9})(4.00 × 10^{-9})/1.0^{2 }= 36.0 N/C

E_{2} = (9.0 × 10^{9})(6.00 × 10^{-9})/0.600^{2 }= 150 N/C

Calculate the x and y components of the electric field at the origin due to the two charges.

A point charge q_{1} = -4.00 nC is at the point x = 0.600 meters, y = 0.800 meters, and a second point charge q_{2} = +6.00 nC is at the point x = 0.600 meters, y = 0.

A) Calculate the magnitude E of the net electric field at the origin due to these two point charges.

B) What is the direction, relative to the negative *x-axis*, of the net electric field at the origin due to these two point charges.

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