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Problem: Using the two measured pipe lengths (L1 = 66 cm and L2 = 40 cm), work out the wavelength of the sound wave. use this to determine the mode numbers and speeds of sound that the two lengths correspond to. You can assume that L1 and L2 represent neighboring resonances (i.e, n and n+2). the pipes are open on one end and closed on the other. frequency of tuning fork is 384 Hz.

FREE Expert Solution

For a pipe closed at one end and open at the other end, the resonance frequency is given by:

f=nv4L

Wavelength:

λ=vf

L1 is greater than L2

Therefore, the resonance frequency of pipe 1 is:

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Problem Details

Using the two measured pipe lengths (L1 = 66 cm and L2 = 40 cm), work out the wavelength of the sound wave. use this to determine the mode numbers and speeds of sound that the two lengths correspond to. You can assume that L1 and L2 represent neighboring resonances (i.e, n and n+2). the pipes are open on one end and closed on the other. frequency of tuning fork is 384 Hz.

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