The time constant in the series RC circuit is:

$\overline{){\mathbf{\tau}}{\mathbf{=}}{\mathbf{R}}{\mathbf{C}}}$, where R is the equivalent resistance, C is the equivalent capacitance, and τ is the time constant.

The final charge stored by the capacitor is expressed as:

$\overline{){\mathbf{Q}}{\mathbf{=}}{{\mathbf{Q}}}_{{\mathbf{0}}}{{\mathbf{e}}}^{\raisebox{1ex}{$\mathbf{-}\mathbf{t}$}\!\left/ \!\raisebox{-1ex}{$\mathbf{\tau}$}\right.}}$, where Q is the final charge and Q_{0} is the initial charge stored by the capacitor.

To find the time constant:

R = 1.1 kΩ = 1.1 × 10^{3}Ω and

C = 20 μF = 20 × 10^{-6}F

τ = (1.1 × 10^{3})(20 × 10^{-6}) = 0.022s

A 20 μF capacitor initially charged to 25 μC is discharged through a 1.1 kΩ resistor. How long does it take to reduce the capacitor's charge to 10 μC?

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